Coat Color Inheritance in basenji


  • @Tiva:

    I think R is here only to make difference between "r" (tricolor) and "R" (red). Just way of writing.

    This link could help you ;) http://www.vetgen.com/canine-coat-color.html

    For basenjis is enough to know about K locus and A locus. Black and brindle are on K locus, red and tricolor are on A locus.

    Black is "the most dominant", than brindle/trindle, red and at the end "the least dominant" is tricolor.

    If your "R" is for red and "r" for tricolor, your BbRr should be the same as Kk ayat (I suppose :) ). This is tri-factored black dog who can produce black, red and tricolor pups.

    Yes i found a punnett square and it had Rr which is why i used it instead of Kk and Yy. :) Thanks for the clearing. anyways ok so Kkayat is KkYy (correct?) so the dog is a black dog that has the reces tri and since it has the dom Red gene and a rec tri that is how you got the Black reds and tris? ok i think i get that now. thank you!


  • ok i have a question. When you are doing a punnett square, lets say you have a dog that is DDKkYy and DDkkYy. Would you put one parent on top and one on the side and do the addition?

    …...kk.....Yy
    Kk..Kkkk…KkYy
    Yy..kkYy...YYyy

    How do you figure out what the puppy is? I dont understand how to take a parents code and put it into the punnett square. I know how to use the punnett square once its ready to be solved but i dont know how to determine where things go and how to evaluate the results (if there are more than 1 letter on each side)


  • Dd kk ayay , Dd kk ayat, Dd kk ayaw, Dd kk ayas, Dd kk aya
    DD Kk ayay = black
    Dd Kk ayay = black
    dd Kk ayay = Blue (dog German)
    dd Kbrk ayay = blue brindle
    DD Kbrk ayay = brindle
    Dd Kbrk ayay = brindle

    DdKbrK ayat


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  • example

    red x whait Dd kk ayay

    black x white
    Dd KbrK ayay

    DD Kk ayay = black x white
    Dd Kk ayay = black x white
    dd Kk ayay = blue (german dog)
    DD Kbrk ayay = brindle
    Dd Kbrk ayay = brindle
    dd Kbrk ayay = fawn brindle

    two
    red x white Dd kk ayat
    black x white Dd KbrK ayat

    possible combination
    DD Kk ayat = black
    Dd Kk ayat = black
    dd Kk ayat = blue (german dog)
    DD Kk atat =black (mask tricolor)
    Dd Kk atat = black (mask tricolor)
    dd Kk atat = blue tricolor
    DD Kbrk ayay = brindle
    Dd Kbrk ayat = brindle
    DD Kbrk atat = trindle
    Dd Kbrk ayat = brindle
    dd Kbrk ayay = blue brindle
    dd Kbrk ayat = blue brindle
    dd Kbrk atat = blue trindle


  • @Monika:

    example

    red x whait Dd kk ayay

    black x white
    Dd Kbrk ayay

    DD kk ayay = red x white
    Dd kk ayay = red x white
    dd kk ayay = blue fawn
    DD Kbrk ayay = brindle
    Dd Kbrk ayay = brindle
    dd Kbrk ayay = fawn brindle

    two
    red x white Dd kk ayat
    black x white Dd KbrK ayat

    possible combination
    DD Kk ayat = black
    Dd Kk ayat = black
    dd Kk ayat = blue (german dog)
    DD Kk atat =black (mask tricolor)
    Dd Kk atat = black (mask tricolor)
    dd Kk atat = blue tricolor
    DD Kbrk ayay = brindle
    Dd Kbrk ayat = brindle
    DD Kbrk atat = trindle
    Dd Kbrk ayat = brindle
    dd Kbrk ayay = blue brindle
    dd Kbrk ayat = blue brindle
    dd Kbrk atat = blue trindle

    Im not sure what all this means. ayat are Yy. umm could you do it with Yy instead of ayay or atat? its just easier for me if you do. thanks


  • Big Y is a red
    small y - tricolor,saddle,agouti and recesiv gen.Can not have four different meanings


  • Misspodhradsky:

    tri factored black dog - Kk ayat
    tri factored red dog - kk ayat

    Use punnett square for K locus and another punnett square for A locus:

    ….......K........k
    k….....Kk.......kk
    k........Kk.......kk

    So, we have Kk (twice) and kk (twice)

    A locus:

    …............ay..........at
    ay….......ayay.....ayat
    at..........ayat......atat

    We got ayay, ayat (twice), atat

    Than put both, K and A locus, together (every K result with every A result):

    Kk ayay - black
    Kk ayat - tri factored black
    Kk atat - tri factored black

    kk ayay - red
    kk ayat - tri factored red
    kk atat - tricolor

    Or, with your letters:
    tri factored black dog - Kk Yy
    tri factored red dog - kk Yy

    ….......K........k
    k….....Kk.......kk
    k........Kk.......kk

    …............Y..........y
    Y….......YY.........Yy
    y..........Yy......yy

    And than again, put all together:

    Kk YY - black
    Kk Yy - tri factored black
    Kk yy - tri factored black

    kk YY - red
    kk Yy - tri factored red
    kk yy - tricolor


  • @Monika:

    Big Y is a red
    small y - tricolor,saddle,agouti and recesiv gen.Can not have four different meanings

    Yes i know that. But when you put ay, at, etc. it confuses me. I need the coding to be is Y,y, K, and k. I think thats it. but i cant follow when people add in different letter cuz i dont understand it :(

    Which sucks cuz when you use letters i know it starts getting easier and easier lol


  • @Tiva:

    Misspodhradsky:

    tri factored black dog - Kk ayat
    tri factored red dog - kk ayat

    Use punnett square for K locus and another punnett square for A locus:

    ….......K........k
    k….....Kk.......kk
    k........Kk.......kk

    So, we have Kk (twice) and kk (twice)

    A locus:

    …............ay..........at
    ay….......ayay.....ayat
    at..........ayat......atat

    We got ayay, ayat (twice), atat

    Than put both, K and A locus, together (every K result with every A result):

    Kk ayay - black
    Kk ayat - tri factored black
    Kk atat - tri factored black

    kk ayay - red
    kk ayat - tri factored red
    kk atat - tricolor

    Or, with your letters:
    tri factored black dog - Kk Yy
    tri factored red dog - kk Yy

    ….......K........k
    k….....Kk.......kk
    k........Kk.......kk

    …............Y..........y
    Y….......YY.........Yy
    y..........Yy......yy

    And than again, put all together:

    Kk YY - black
    Kk Yy - tri factored black
    Kk yy - tri factored black

    kk YY - red
    kk Yy - tri factored red
    kk yy - tricolor

    OH! ok! so you dont do them all together. you do letter with letter and then add them! Oh ok!!! Thank you soo much! That helps alot!


  • letter "a" located in the locus A

    letter y,t,w,a, talking about hair color
    otherwise you can not save


  • Letter D intense color
    letter d lightened the color


  • @Tiva:

    Kk YY - black
    Kk Yy - tri factored black
    Kk yy - tri factored black

    kk YY - red
    kk Yy - tri factored red
    kk yy - tricolor

    Where did you get the bold ones. I understand how to get the others but if you do it and add them together it makes no sense. …to me

    OR do you have to do

    1....2
    3....4

    1...2
    3...4

    do you have to do 1 with 1, 1 with 2, 1 with 3, 1 with 4....then 2 with 2, 2 with 3, 3 with 4....then 3 with 3, 3 with 4....then 4 with 4. and then take all the alike genes and group them. then take all the unalike genes and
    that is how you go the 2 extra genes?
    (I used 1,2,3,4 just to make it easier to understand than using letters K, Y, etc.)


  • Tiva helping me, thank you


  • I am beginning to be wrong.I'm going to sleep until tomorrow. (11 _55 PM)


  • from K locus we got:
    Kk (and again Kk) - 1
    kk (and again kk) - 2

    from A locus we got:
    YY - a
    Yy (and again Yy) - b
    yy - c

    1 + a = 1a (Kk YY)
    1 + b = 1b (Kk Yy)
    1 + c = 1c (Kk yy)
    2 + a = 2a (kk YY)
    2 + b = 2b (kk Yy)
    2 + c = 2c (kk yy)


  • @Tiva:

    from K locus we got:
    Kk (and again Kk) - 1
    kk (and again kk) - 2

    from A locus we got:
    YY - a
    Yy (and again Yy) - b
    yy - c

    1 + a = 1a (Kk YY)
    1 + b = 1b (Kk Yy)
    1 + c = 1c (Kk yy)
    2 + a = 2a (kk YY)
    2 + b = 2b (kk Yy)
    2 + c = 2c (kk yy)

    Oh ook i think i get it now, thx for the help in clearifying it. so would "A" always be YY, "b" always be Yy and "C" always be yy? or is that just for this example?


  • Just for that example.


  • oh. so how do you know what to use then. :(

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    listed disorders for which there is a general consensus among those investigating in this field and among veterinary practitioners, that the condition is significant in this breed. Where the mode of inheritance is known, this information is included on the linked disease